## NCERT Solutions for Class 11 Maths Chapter 12 – Introduction to Three Dimensional Geometry Ex 12.3

#### Page No 277:

#### Question 1:

Find the coordinates of the point which divides the line segment joining the points (–2, 3, 5) and (1, –4, 6) in the ratio (i) 2:3 internally, (ii) 2:3 externally.

#### Answer:

(i) The coordinates of point R that divides the line segment joining points P (

*x*_{1},*y*_{1},*z*_{1}) and Q (*x*_{2},*y*_{2},*z*_{2}) internally in the ratio*m*:*n*are
.

Let R (

*x*,*y*,*z*) be the point that divides the line segment joining points(–2, 3, 5) and (1, –4, 6) internally in the ratio 2:3
Thus, the coordinates of the required point are.

(ii) The coordinates of point R that divides the line segment joining points P (

*x*_{1},*y*_{1},*z*_{1}) and Q (*x*_{2},*y*_{2},*z*_{2}) externally in the ratio*m*:*n*are
.

Let R (

*x*,*y*,*z*) be the point that divides the line segment joining points(–2, 3, 5) and (1, –4, 6) externally in the ratio 2:3
Thus, the coordinates of the required point are (–8, 17, 3).

#### Question 2:

Given that P (3, 2, –4), Q (5, 4, –6) and R (9, 8, –10) are collinear. Find the ratio in which Q divides PR.

#### Answer:

Let point Q (5, 4, –6) divide the line segment joining points P (3, 2, –4) and R (9, 8, –10) in the ratio

*k*:1.
Therefore, by section formula,

Thus, point Q divides PR in the ratio 1:2.

#### Question 3:

Find the ratio in which the YZ-plane divides the line segment formed by joining the points (–2, 4, 7) and (3, –5, 8).

#### Answer:

Let the YZ planedivide the line segment joining points (–2, 4, 7) and (3, –5, 8) in the ratio

*k*:1.
Hence, by section formula, the coordinates of point of intersection are given by

On the YZ plane, the

*x*-coordinate of any point is zero.
Thus, the YZ plane divides the line segment formed by joining the given points in the ratio 2:3.

#### Question 4:

Using section formula, show that the points A (2, –3, 4), B (–1, 2, 1) and are collinear.

#### Answer:

The given points are A (2, –3, 4), B (–1, 2, 1), and.

Let P be a point that divides AB in the ratio

*k*:1.
Hence, by section formula, the coordinates of P are given by

Now, we find the value of

*k*at which point P coincides with point C.
By taking, we obtain

*k*= 2.
For

*k*= 2, the coordinates of point P are.
i.e., is a point that divides AB externally in the ratio 2:1 and is the same as point P.

Hence, points A, B, and C are collinear.

#### Question 5:

Find the coordinates of the points which trisect the line segment joining the points P (4, 2, –6) and Q (10, –16, 6).

#### Answer:

Let A and B be the points that trisect the line segment joining points P (4, 2, –6) and Q (10, –16, 6)

Point A divides PQ in the ratio 1:2. Therefore, by section formula, the coordinates of point A are given by

Point B divides PQ in the ratio 2:1. Therefore, by section formula, the coordinates of point B are given by

Thus, (6, –4, –2) and (8, –10, 2) are the points that trisect the line segment joining points P (4, 2, –6) and Q (10, –16, 6).

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