NCERT Solutions for Class 12 Maths Chapter 5 – Continuity and Differentiability Ex 5.2
Page No 166:
Question 1:
Differentiate the functions with respect to x.
Answer:
Let f(x)=sinx2+5, ux=x2+5, and v(t)=sint
Then, vou=vux=vx2+5=tanx2+5=f(x)
Thus, f is a composite of two functions.

Alternate method

Question 2:
Differentiate the functions with respect to x.
Answer:

Thus, f is a composite function of two functions.
Put t = u (x) = sin x

By chain rule,
Alternate method
Question 3:
Differentiate the functions with respect to x.
Answer:

Thus, f is a composite function of two functions, u and v.
Put t = u (x) = ax + b

Hence, by chain rule, we obtain
Alternate method

Question 4:
Differentiate the functions with respect to x.
Answer:

Thus, f is a composite function of three functions, u, v, and w.

Hence, by chain rule, we obtain

Alternate method

Question 5:
Differentiate the functions with respect to x.
Answer:
The given function is
, where g (x) = sin (ax + b) and
h (x) = cos (cx + d)

∴ g is a composite function of two functions, u and v.

Therefore, by chain rule, we obtain

∴h is a composite function of two functions, p and q.
Put y = p (x) = cx + d

Therefore, by chain rule, we obtain

Question 6:
Differentiate the functions with respect to x.
Answer:
The given function is
.

Question 7:
Differentiate the functions with respect to x.
Answer:

Question 8:
Differentiate the functions with respect to x.
Answer:

Clearly, f is a composite function of two functions, u and v, such that

By using chain rule, we obtain

Alternate method

Question 9:
Prove that the function f given by
Answer:
The given function is
It is known that a function f is differentiable at a point x = c in its domain if both
To check the differentiability of the given function at x = 1,
consider the left hand limit of f at x = 1


Since the left and right hand limits of f at x = 1 are not equal, f is not differentiable at x = 1
Question 10:
Prove that the greatest integer function defined by
is not
differentiable at x = 1 and x = 2.
Answer:
The given function f is
It is known that a function f is differentiable at a point x = c in its domain if both
To check the differentiability of the given function at x = 1, consider the left hand limit of f at x = 1


Since the left and right hand limits of f at x = 1 are not equal, f is not differentiable at
x = 1
To check the differentiability of the given function at x = 2, consider the left hand limit
of f at x = 2


Since the left and right hand limits of f at x = 2 are not equal, f is not differentiable at x = 2